Not sure if you got it...
Just in case anyone is unclear I'll try putting it another way...
Pretend that Amel and Anery are actually alleles. This means that they sit in the same slot on the chromosome, so on any given single chromosome, there could not be both an Anery and an Amel gene, since only one or the other would exist in that slot.
For the rest of this post, we will pretend that these two are alleles as mentioned above. (In reality they aren't like that, but this makes an easier illustration.)
So, if you had a pair of Amels, a pair of Anerys, and a pair of Normals that were NOT het, what kind of breeding could you do?
- Breed the Amel to the normal, and you'd get normals het for amel. Technically, these animals are het for Amel AND Normal, because that's what "het" means: the paired genes (normal and amel) are not the same as each other. Breed these hets together to get some amels, of course.
- Breed the Anery to the normal. You'd get normals het for Anery. Breed these hets together to get some Anerys.
- So, given our situation, when you breed one of these Amels to one of these Anerys, what would you get?
You would get offspring that carried one Amel gene paired with one Anery gene. Would they be Normals?
No, because the corresponding Normal gene is not present in these offspring to offset the effect of either gene. So you'd actually get offspring that expressed both traits. You'd get something like Snows in that case.
And, are these "Snow" offspring hets? In fact, they are hets, because remember, "het" means that the paired genes are not the same--Anery is paired off with Amel.
So, if you were to breed two of those "snows" together, the offspring would be Amels, Anerys, and Snows.
That's not how Amel, Anery and Snow actually work, but it is how the Motley and Striped traits work.
Oh, the point is that "motley het for striped" and "striped het for motley" and "motley striped" and "heterozygous motley striped" are all exactly the same thing.