Bloodred is NOT a simple recessive gene like amelanism, but if you have a snake that is the product of a bloodrd crossed with (fill in the blank), then your out-crossed bloodred will carry all of the simple recessive genes that come together to make a bloodred, assuming that the bloodred morph is a combination of simple recessive genes. When your snake is then crossed with a bloodred, the product of that pairing will likely produce some babies that are bloodred, and the others will be "het" for all of the characteristics.
Quite frankly we don't know how this all works out, and simple punnett squares don't help in any way. However, if bloodred is a genetically passable trait from parents to offspring (we know it is because bloodred x bloodred produces bloodreds), then bloodred out-crosses also have to have inherited those genes from their bloodred parent. How it works out genetically may be a bit fuzzy, but just because we don't fully understand the process doesn't mean something isn't happening there
It may not be completely accurate to say that an animal is "het" for bloodred. However, when I hear or use that terminology, I do so with the understanding that the animal in question is the product of breeding a bloodred to another morph, and when I breed this "het" to a bloodred, I expect to get some bloodreds in the clutch.
Now, the percentage of bloodreds to be expected? That's another story all together
