Anery A's Dominance over Caramel?

Is anery a dominant over caramel? On Serpenco's page it says an anery motley was hatched from caramel motley parents, and anery a might be dominant over caramel. Any more info on this Rich?
Reason I ask is next year I would like to breed my caramel mot with one of my anery motleys to get motleys het for anery/caramel. In the F2 will I end up with all anery motleys?
Thanks for any info.
joe clark

Yes, it appears that 'A' Anerythrism dominates Caramel when both are homozygous in the same animal.

This year has been really odd with hatchlings. I've been producing Butter Motleys for several years now, but all of a sudden this year I am getting a fair number of Snow Motleys hatching out of the eggs from Butter Motley parents. Also I am getting a substantial number of Snows hatching out from eggs with Butter parents. Of course, I will be keeping most of these just to see what they will turn out looking like. There is a good possibility that the Snow Motleys with one parent being het are quad homozygous animals (Caramel, Motley, Amelanism, and 'A' Anerythrism). Heck, I can't remember if I've gotten any of them when both parents were Butter Motleys, but if so, they would definitely be quad homozygous animals.

Hmm, seems to me I also got some Anerythristic Motleys in some of those clutches, so with one parent being a Butter Motley, of course they would have to be het for Butter.

Reason I ask is next year I would like to breed my caramel mot with one of my anery motleys to get motleys het for anery/caramel. In the F2 will I end up with all anery motleys?

Bear in mind that if you breed a Caramel Motley with an Anery Motley, your F1s will be Motleys het for Caramel and Anerythrism. Now when you breed those offspring together, the problem you are going to have is that any Anerythristic Motleys in the bunch *may* be homozygous for Caramel as well, but I'm not sure you will be able to tell visually. I only have that one Anery Motley from Caramel Motley parents, but it hasn't reached full maturity yet. So I don't know if it will have identified features or not to tell you that it is also homozygous for Caramel.

Working with motleys het for caramel and anery, you will get 1/4 homo anery and 1/4 homo caramel. The overlap on that is only going to be the "loss" of 1/4 of your caramel motleys because that one in 4 will instead be Anery.

IOW, you get the standard 9:3:3:1 ratio, with 3 anerys, 3 caramels, and 1 Anery+Caramel.

Het caramel to het caramel only produces 4 in 16 caramels, so I don't think it's going to be a major disadvantage. As far as "additional mutants" hatching, you will be getting 7 in 16 (4 being anery) instead of 4 in 16... I guess it depends on whether or not you want only one specific type to hatch.

IOW, you get the standard 9:3:3:1 ratio, with 3 anerys, 3 caramels, and 1 Anery+Caramel.

Just for the record, in practicality, things don't really work out like the statistics might indicate. In other words, if you breed single het recessive animals together, the statistical ratio will be 25% homozygous recessive, 25% normals, and 50% het offspring. But you cannot expect that if you hatch 16 eggs, that you will get 4 homozygous animals, 8 normal colored hets, and 4 regular non-heterozygous hets.

What it REALLY means is that EACH animal has a 25% chance of being a homozygous animal, 25% chance of being a normal, and a 50% chance of being a het. This is a VERY important distinction! It will be one of the three, but the statistics are only giving the odds of what that will be.

When people talk about a 66 percent het, what they are talking about are the normal colored animals in the above breeding. Each one has a 66 percent chance (2 out of 3) of being heterozygous for the gene that was heterozygous in both parents.

In reality what you get will be directly related to your *luck* quotient multiplied by the statistical probability. So effectively you can get anywhere from NONE of the homozygous animals, to having them ALL homozygous, depending on how good your luck is.

In the scenario of this thread, working with double het animals is a true test of your sanity. It is very frustrating to see a large clutch of newly hatched babies with a good percentage of them having gene #1, another percentage having gene#2, but NONE of the animals with both genes expressed together. This can be doubly so if one of the two genes will mask the other, leaving you no way of knowing unless you do breeding trials with the individuals when they reach maturity.

To perhaps help this to be a little clearer, imagine that you have bred two animals together that are het for 'A' Anerythrism and Amelanism. The results of this pairing was 16 eggs. 60 some days later, 15 of the 16 have hatched and you have not gotten a snow corn. Does that 16th egg HAVE to contain a Snow Corn? Analyze why this answer has to be NO and you will get a better feel for the practical applications of this genetics stuff.

Originally posted by Rich Z
The results of this pairing was 16 eggs. 60 some days later, 15 of the 16 have hatched and you have not gotten a snow corn. Does that 16th egg HAVE to contain a Snow Corn?

And the answer is Yes! That's why Frank Pinello got the one this year that is part one morph and part the other.

But seriously, I know we all tend to not mention that these are not statistical probabilities. The statistics are helpful though. You know you that the more 6-sided dice you roll, the better odds you have of getting a 6.

So far my luck quotient has been pretty good. This year out of 22 eggs (each with a 1 in 16 chance of being snow) I got 2 snows. We'll see if they are both females, which would be uncool, but that's only a 1 in 4 chance.

Serp, do you spend much time in casinos?

j/k!


^Curtis