Testbreeding Buf x Toffee

First testbreeding between the buf and the toffee gene. ( from me )
Auratumstriped ( Toffee-amel-striped ) x Orange het motley ( Buf-amel het motley )
6 eggs ( Both genes are dominant)
4 Orange colored motleys
2 Orange colored ( one still in the egg )
There are no visual difference in the animals, not in the motleys and not in the other animals.
All 6 are orange colored ( lucky ? )Or is someone Homo ( the parents )The Orange not possible that she is homo, the auratum could be homo becouse he is from auratumstriped x the same.

"Or is someone homo" for what? Orange x Auratum would produce all animals expressing the amel gene, because both parents are homo amel. Whether or not they're Orange or Auratum is for you to decide. Pictures would be very helpful, especially to help breach the language barrier.

Are the babies "just" amel? and toffee and buf were not the same, so the babies are het toffee and buff?

Or are the babies homo amel and homo toffee/buf, which are the same gene?

I second Robbie's question- is someone homo _what_?

bwahahaha Nanci asked if someone was homo!

ANYWAY! i would love to see pictures

Ok
Buf is a dominant gene discoverd in 2001 in holland its a hypoerythristic gene and made a amel into orange.
Toffee is also a dominant gene discoverd in i beleef 2006-2008 in Germany and looks the same and act the same.
This discoveries are made 200 km from each other, the discossion is, if this gene is the same or not the same.
But there is never made a testbreeding between theese genes, so i get a auratumstriped ( Toffee-amel- striped)male and cross him to a Orange het motley female ( Buf-amel-het motley )Becouse this genes are dominant there must be a hetro and a homosygoot form, but they look the same you can not tell witch one is het ore homo, not until breedings are done.
Example Buf
Bn = Buf B for buf, n for wildtype, when we cross a buf to a buf , the punnet square says.

-----B--------n
B----BB------Bn
n----Bn------nn

BB is the buf in homo form
Bn is the buf in hetero form
nn is wildtype

The BB and the Bn looks the same

The Toffee gene act the same.
Now a made this first testbreeding from Buf-amel x Toffee-amel ( let the motley and stripe away )
One thing we now everything must be amel 100%
I got 6 eggs al 6 are amel that ok ,but also Buf ore Toffee becouse all the offspring is Orange .I can not see any difference between them as a wrote.
What i ment with the homo thing is. If the toffee is homosygoot TT then al the ofspring is Toffee-amel ( auratum )But where is the buf there must be buf in the game.If buf and toffee are the same then all animals look the same ( Orange ).If buf and toffee is not the same , this breeding would produce differentsie thats my opinion

Originally Posted by slangenbroed

Becouse this genes are dominant there must be a hetro and a homosygoot form, but they look the same you can not tell witch one is het ore homo, not until breedings are done.
Example Buf
Bn = Buf B for buf, n for wildtype, when we cross a buf to a buf , the punnet square says.

-----B--------n
B----BB------Bn
n----Bn------nn

BB is the buf in homo form
Bn is the buf in hetero form
nn is wildtype

The BB and the Bn looks the same

The Toffee gene act the same.
Now a made this first testbreeding from Buf-amel x Toffee-amel ( let the motley and stripe away )
One thing we now everything must be amel 100%
I got 6 eggs al 6 are amel that ok ,but also Buf ore Toffee becouse all the offspring is Orange .I can not see any difference between them as a wrote.
What i ment with the homo thing is. If the toffee is homosygoot TT then al the ofspring is Toffee-amel ( auratum )But where is the buf there must be buf in the game.If buf and toffee are the same then all animals look the same ( Orange ).If buf and toffee is not the same , this breeding would produce differentsie thats my opinion

If all hatchlings look the same orange way then it is likely that buf and toffee are the same gene and that at least one of the parents are homozygote for the dominant gene.

Originally Posted by NiklasTyreso

If all hatchlings look the same orange way then it is likely that buf and toffee are the same gene and that at least one of the parents are homozygote for the dominant gene.

They all shed now and i see a little variation just as in a orange only clutch, if a make a pic you can't see the different.Maybee iff they growing up ???? Lets feed them and wait.

Originally Posted by NiklasTyreso

If all hatchlings look the same orange way then it is likely that buf and toffee are the same gene and that at least one of the parents are homozygote for the dominant gene.

Thinking it over again, what I first wrote might be wrong.

If one parent is homozygote fore a dominant (orange) trait all hachlings should show that trait.

The traits might mask each other, or they might enhange each other. You can not know.

The best testbreeding would be to breed two known heterozygote:
Het dominant Buf amel X Het dominant Toffe amel
Then you would get about 25 % without buf or toffe
50% with buf or toffe
25 % with double trait dominant het buf+ dominant het toffe (extreme orange?)
If you got 75 % orange but 25 % of them look differen orange, then it might be different genes.

If you have two different orange dominant genes and one parent is het dominant and the other is homo for the other dominant gene, then all should be orange but 50% should be double hets for two dominant genes. Then there probably would be that half of the clutch would be different in the orange than the other half.

If you get no clear proportions in the clutch, but just a gradient of natural variation, then buf and toffe is probably just the same gene.

So, calculate proportions for the outcome you should get from what you know of the parents, if they are het or homo for the dominant genes.
Let the proportions guide you.

(I always forget about it being dominant- sorry!)