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caramel And Anerythristic

RO8 H

RO8 H

New member
I have acquired some babies from the above parents. One of the babies is a motley and one shows some motley traits and the 3rd one just has normal patterning so there was obviously motley in one or both of the parents as het. first of all I would like to know what the offspring would be genetically if there were no other hets involved. I will also post pics of the babies and one is dark brown. I assume that she is anery. the others are very pale and almost pinkie in colour. Possible lavender.
 
Pictures will definitely help. If you cross the two above without hets you would get all normal het caramel and anery. There must have had some hidden hets if they are all not brown (typical normal coloration). An anery (also called black albino) will be shades of grey (varies with morphs).

Male: Anery Female: Caramel

Phenotype:1 / 1 Normal het Anery, Caramel


Genotype:1 / 1 Normal het Anery, Caramel

If both were het for lavender then you could possibly get lavenders but again, pictures will help tremendously.

Male: Anery het Lavender Female: Caramel het Lavender

Phenotype:1 / 4 Lavender het Anery, Caramel
3 / 4 Normal het Anery, Caramel 66% poss het. Lavender


Genotype:1 / 4 Lavender het Anery, Caramel
1 / 4 Normal het Anery, Caramel
1 / 2 Normal het Anery, Caramel, Lavender
 
I tried entering the morphs into the corn calc and received the same results. There certainly were not any normals in this batch. I also viewed both parents and can confirm that they were anery and caramel
 
The 3rd baby is even lighter in colour than that one but has just been fed so i left him alone. Is it possible to get ghosts from that pairing.
 
If they where both het hypo, it is possible.
That means the parents are anery het, hypo and caramel het. anery, hypo and both are motley too
 
Thank you. There was clearly something going on in the parents to produce offspring like these. if there were no hets they would of come out normals het anery and caramel.
 
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