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Question for genetic wizzards

Marcel Poots

Marcel Poots

Young, handsom member
I what am I doing wrong here?

Can someone draw me a chart (the way I did it wrong) that will result in the answer of the genetic wizzard?
 

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If s is recessive for stripe, z is recessive for zigzag (which doesn't behave as a recessive trait actually, so that's misleading), and a is recessive for amel, then your grid should look like the following:


Across the top would be: ZSA, ZsA, zSA, zsA.
Down the side would be: ZSA, ZSa

The first row would be: ZZSSAA, ZZSsAA, ZzSSAA, ZzSsAA
The second row would be: ZZSSAa, ZZSsAa, ZzSSAa, ZzSsAa

Therefore you have a 1 in 8 chance of getting any of the above combinations. If you don't put placeholders for the wildtype genes, you wind up forgetting combinations. To correct your diagram, Marcel, you need to have an extra column labeled sz, since it's possible for the offspring to inherit both of the genes the female has. Again, zigzag doesn't act like a regular recessive... but if it did, that's how you would treat it.

-Kathryn
 
But the male is only het Amel so Vertical should only have A right?.. That's why I donlt get it. I dont' understand the methode.
I just picked three genes. I know ZigZag is not really recessive. But my question is now how do you come up with the horizontal markers and vertical markers (placeholders)?
 
I think you need to make is simpler for me (lol, bare with me). Can you make a Punnett square. with only Het Amel and Het Stripe? Aa, Ss. What will the horizontal and vertical row be?
 
.......AS.... As....aS....ss
.
.
A AASS AsSS AsSS AsSs
S
.
.
a aAaS aAas aaaS aass
a


Aaarrggg I am lost..
 
Ok... If your male was het stripe and your female was het amel, this is how they'd look:

Male: AASs
Female: AaSS

Across the top would be: AS As
Down the side would be: AS aS

The first row's results would be: AASS AASs
The second row's results would be: AaSS AaSs

Therefore, you'd have a 1/4 chance of getting a particular combination (AASS - normal, AASs - het stripe, AaSS - het amel, AaSs - het amel stripe).

-Kat
 
Marcel,

Each parent has two of each letter, and each sperm/egg has only one of each letter.

Each offspring gets one letter from the sperm, and one letter from the egg, so it has two of each letter.

Use the # button on the top of the post, or use the "code" tag, to insert code and you can make tables that line up.

You'll want to use the preview button to double check...

Like this:
Code: 
[color=blue]AaSs[/color] x [color=red]AaSs[/color] (both normals double het amel stripe)

     [b][color=blue] A S    A s    a S    a s[/color][/b]
[b][color=red]AS[/color][/b]   [color=red]A[/color][color=blue]A[/color][color=red]S[/color][color=blue]S[/color]   [color=red]A[/color][color=blue]A[/color][color=red]S[/color][color=blue]s[/color]   [color=red]A[/color][color=blue]a[/color][color=red]S[/color][color=blue]S[/color]   [color=red]A[/color][color=blue]a[/color][color=red]S[/color][color=blue]s[/color]
[b][color=red]As[/color][/b]   [color=red]A[/color][color=blue]A[/color][color=red]s[/color][color=blue]S[/color]   [color=red]A[/color][color=blue]A[/color][color=red]s[/color][color=blue]s[/color]   [color=red]A[/color][color=blue]a[/color][color=red]s[/color][color=blue]S[/color]   [color=red]A[/color][color=blue]a[/color][color=red]s[/color][color=blue]s[/color]
[b][color=red]aS[/color][/b]   [color=red]a[/color][color=blue]A[/color][color=red]S[/color][color=blue]S[/color]   [color=red]a[/color][color=blue]A[/color][color=red]S[/color][color=blue]s[/color]   [color=red]a[/color][color=blue]a[/color][color=red]S[/color][color=blue]S[/color]   [color=red]a[/color][color=blue]a[/color][color=red]S[/color][color=blue]s[/color]
[b][color=red]as[/color][/b]   [color=red]a[/color][color=blue]A[/color][color=red]s[/color][color=blue]S[/color]   [color=red]a[/color][color=blue]A[/color][color=red]s[/color][color=blue]s[/color]   [color=red]a[/color][color=blue]a[/color][color=red]s[/color][color=blue]S[/color]   [color=red]a[/color][color=blue]a[/color][color=red]s[/color][color=blue]s[/color]


(Easy enough, I just put all of this inside a "code" tag, LOL)
PHP: 
[color=blue]AaSs[/color] x [color=red]AaSs[/color] (both normals double het amel stripe)
     [b][color=blue] A S    A s    a S    a s[/color][/b]
[b][color=red]AS[/color][/b]   
[color=red]A[/color][color=blue]A[/color][color=red]S[/color][color=blue]S[/color]   
[color=red]A[/color][color=blue]A[/color][color=red]S[/color][color=blue]s[/color]   
[color=red]A[/color][color=blue]a[/color][color=red]S[/color][color=blue]S[/color]   
[color=red]A[/color][color=blue]a[/color][color=red]S[/color][color=blue]s[/color]
[b][color=red]As[/color][/b]   
[color=red]A[/color][color=blue]A[/color][color=red]s[/color][color=blue]S[/color]   
[color=red]A[/color][color=blue]A[/color][color=red]s[/color][color=blue]s[/color]   
[color=red]A[/color][color=blue]a[/color][color=red]s[/color][color=blue]S[/color]   
[color=red]A[/color][color=blue]a[/color][color=red]s[/color][color=blue]s[/color]
[b][color=red]aS[/color][/b]   
[color=red]a[/color][color=blue]A[/color][color=red]S[/color][color=blue]S[/color]   
[color=red]a[/color][color=blue]A[/color][color=red]S[/color][color=blue]s[/color]   
[color=red]a[/color][color=blue]a[/color][color=red]S[/color][color=blue]S[/color]   
[color=red]a[/color][color=blue]a[/color][color=red]S[/color][color=blue]s[/color]
[b][color=red]as[/color][/b]   
[color=red]a[/color][color=blue]A[/color][color=red]s[/color][color=blue]S[/color]   
[color=red]a[/color][color=blue]A[/color][color=red]s[/color][color=blue]s[/color]   
[color=red]a[/color][color=blue]a[/color][color=red]s[/color][color=blue]S[/color]   
[color=red]a[/color][color=blue]a[/color][color=red]s[/color][color=blue]s[/color]
 
Last edited:
Kat, Serp,

Both of you are great! Thanks a lot.... To proof if I get it can you say if this picture is right?
 

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  • vraag4.jpg
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If the Male amel isn't het stripe and the Female het stripe isn't het amel, then:
(Gotta have both of the genes in each outcome. :) )

Code: 
[color=blue]aaSS[/color] x [color=red]AASs[/color] (Amel x Normal het stripe)
     [b][color=blue] a S    a S[/color][/b]
[b][color=red]AS[/color][/b]   [color=red]A[/color][color=blue]a[/color][color=red]S[/color][color=blue]S[/color]   [color=red]A[/color][color=blue]a[/color][color=red]S[/color][color=blue]S[/color]
[b][color=red]As[/color][/b]   [color=red]A[/color][color=blue]a[/color][color=red]s[/color][color=blue]S[/color]   [color=red]A[/color][color=blue]a[/color][color=red]s[/color][color=blue]S[/color]

Or in honesty, even more simply since the male can only throw one gene combo:

Code: 
[color=blue]aaSS[/color] x [color=red]AASs[/color] (Amel x Normal het stripe)
     [b][color=blue] a S[/color][/b]
[b][color=red]AS[/color][/b]   [color=red]A[/color][color=blue]a[/color][color=red]S[/color][color=blue]S[/color] 
[b][color=red]As[/color][/b]   [color=red]A[/color][color=blue]a[/color][color=red]s[/color][color=blue]S[/color]

So 50% Hets for Amel and Stripe, 50% Hets for Amel only.
 
Back up a bit Marcel. :)

With your example:

The male you used is an amel. He has exactly two a's and two s's. Since he is amel, and not het stripe, he is:
aa SS

The female is a normal het stripe. She has exactly two a's and exactly two s's.
AA Ss

The male can only give ONE a and ONE s. Since they are both the same a and the same s, his sperm are all:
as

The female can only give ONE a and ONE s. Since her a's are the same, she can only give a capital A. Since she has two different s's, her eggs can be:
AS or As

Make those two into your Punnett square, and you get Hurley's second example. :)
 
The male can only give ONE a and ONE s. Since they are both the same a and the same s, his sperm are all: as
Click to expand...

You mean aS, don't you? Since S represents the wild type?

-Kat
 
Yeah, that too. :)

Thanks. It's been a while since I've used the letters. Now I remember why I stopped: I don't catch the difference between big and small letters. ;)
 
Oh, btw... I asked the questions because I am trying to make a program that can visualize these punnets... Harder than it looks ;) I have a long way to go..
 

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  • vraag5.jpg
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Just read Hurley's...

Hurl... your top row should be aS AS...
Click to expand...

If the Male amel isn't het stripe and the Female het stripe isn't het amel, then:
Click to expand...

....Male amel not het stripe... aaSS --> aS and aS
....Female normal het stripe... AASs --> AS and As

Top row is the male, so it should be aS and aS.


Kat,
I don't get what you mean. (?)
 
Cool. It was actually a program I was writing that helped me work out the process of doing the calculations, and before I finished the program, I found I didn't need it anymore, and I had picked up a bunch of shortcuts so I don't have to do Punnett Squares anymore. ;)

The biggest difficulty is translating back to "human" language with the results.

What language are you working with? (C++, etc.)
 
Serpwidgets said:

The biggest difficulty is translating back to "human" language with the results.
Click to expand...

That's the easy part for me.. I have arrays with :

HeteroType['Aa', 'Bb' etc..] and
HetroString['het Amel', 'Het AneryB'..etc]
 
Hey Marcel,

Cool idea, couple notes:

Butter isn't a simple recessive trait, it's a combo
of amel and caramel...so in your program butter
should be aaff.

Also, stripe and motley seem to act as alleles,
so they'd be something along the lines of
D = normal, d = motley, d' = stripe....or whatever.
Superscript an m and an s, etc.

Problem with that, too, is that striped motleys
bred together do not seem to yield 25% stripes
as one would expect from a recessive gene pair.
 
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