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What would a.....

Winter Steel 69

New member
I have an Amel het Lavender , and a Snow het Opal.
What would my hatchlings be? Ive searched the forum and tried Mick's Corn P. Predictor. No luck so far. I think a Snow is made from Anery-A x Amel , and a Opal from Amel x Lavender. Im thinking (hoping) mostly Amels het Lavender in the F1.
 
Actually

An amel het lav paired with a snow het opal should yield approx.

50% Amelanistic het anery, and lav
25% Amelanistic het anery
25% amelanistic lavender

I believe that is what would be produced...
 
All amel.........

Some Opal. (maybe? hopefully!)

All het anery.

Some amels het Lavender. Of the non Opal, 66% of the amel will be het Lavender. You just won't know which ones.

It does get tricky!
 
Re: By phenotypes...

Serpwidgets said:
Statistically, you'd get:
25% opal het anery
75% amel het anery and lavender (het snow/opal)
D'oh! I must've had a brain prolapse when I was writing that. ;) Clint is right. Somehow I kept thinking the one was an opal. They'd be:
25% opal (het anery)
75% amel (het anery, 66% poss het lavender)

:)

To Winter Steel 69 (interesting, I was born in the winter of '69, hehe) and anyone else interested in this stuff: The easiest way to do these is to break them down into the components. Instead of "snow het opal" look at it as "anery amel het lavender." This is much easier to cross to an amel het lavender, as you can see the traits (homo and het) matching up. :)

In my wacky "I hate Mendelian pair notation" notation, it would look like this:
Code:
   EA/L
x   A/L
To get the answers for recessive traits, just pair each letter to itself only. Remember, anery doesn't affect amel, etc, so do the "A" stuff, then the "E" stuff, then the "L" stuff, etc. (IOW, never-ever-ever-ever pair A with anything but A.)

  • Paired
  • over the slash (AA) gives "all expressing."
  • across the slash (A/A) gives "half expressing, half het"
  • under the slash (/AA) gives "quarter expressing, the rest 66% poss het"

    Alone
  • over the slash (A) gives "all het"
  • under the slash (/A) gives "50% poss het"

Try it out with this one, hehe:
Code:
  ABC/D
x   A/BDE
 
If I understand the question correctly, you're saying you have a poss het lav and want to find out if it's het or not. There are two ways to determine this:

1- breed it to a lavender (if it's het, expect ~50% lavs)

2- breed it to a known het for lav (if it's het, expect ~25% lavs)

Snow is the combination of amel and anery. Neither of those have anything to do with the lavender gene, so they wouldn't make any determination either way. :)
 
Het to het is iffy!..........

The only way crossing het to het will prove out is if you get Lavs and prove it is het Lav. Getting no Lavs only proves you didn't get any, it may not be het or it may be bad luck in the odds.

Example:
I have a female amel het for Caramel and Motley. I crossed her with a Caramel het amel and Motley. I had eight eggs in the clutch, three normals, three Caramels, one amel and one Butter, none of which are Motley. Statistically, two of them should have been Motley. Of course, the larger the clutch size, the better your chances are but there is still the possibility that you'll get no mutation showing from a het to het cross.

In my opinion, to really prove if it's het Lav, go with a Lav cross. In a small clutch you may still not get any Lavs (really bad luck!) but at least you'll know for sure that they are het Lavender.
 
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