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;>) Lots of questions!

cmariles

cmariles

New member
The second part is this:
I am to breed a male motley butter with a female anrey blood. My gen wiz says my f1 or first clutch will be 100% motley! Yay... wait motley what?!?! I then realized that as they are both showing recessive traits and none are matching traits is the bloodred going to express itself eventually? Now according to my gen wiz the odds are against me getting a Sulfer (which was the orig goal). By breeding the best looking of the second clutch together should produce a rainbow of morphs due to the known hets.

Once again, thanks for your patience and guidance.

Carlos
 
If you have a motley caramel amel x anery blood you will not get any motleys in the first generation unless the anery blood is also motley or het for motley.

with motley caramel amel x anery blood your result would be:
100% normals het motley caramel amel anery blood

You can then breed those offspring to eachother to get quite the variety of offspring. In the resulting offspring from that pairing the odds of you getting offspring with all 5 of those traits will be worse than getting ones with 4 of those traits will be worse then getting one with 3 of those traits, etc...

So your odds of getting a sulfer (caramel amel blood) from the pairing of the offspring will be worse than your odds of getting, for instance, just normals or just amels or just bloodred/diffused, etc....but will be better than your odds of getting a snake which shows all 5 traits (motley caramel amel anery blood).
 
What ZoologyGirl said. :bird: (god i love emoticons)

What program did u use? I think those are weird results or do the snakes have hets??
 
Many thanks to you both! It is so wild to me that I will get normals! I must have missed something in my reading!
I used the MP Generic Genetic Wizard. It was recommended by a thread on this site. It could have been user error. Oh, both snakes are showing motley.
Thanks for clearing that up for me.

:cheers:

Carlos
 
I show a 1.17% chance of getting a sulfur in your f2. Roughly half would be motley's as well
 
The cause for all your confusion is that in your other thread, you say you have a butter motley and an anery motley, yet in this thread, you have a butter motley and an anery bloodred. So which pattern IS your anery?
 
Funny thing....

My fiancee and I recently had a heated discussion. Nothing to do at all with my hobby thank heavens! I apparently think I include all that is important in my discussions when even after re reading what I have written I am still not always clear about what I am trying to say.

I have apologized to her and now to you all Sorry! :eek:

The male snake is a butter motley(Moe). The female is a anrey motley bloodred (Elvira).

Part of the solution in my personal life is to try to remember that just because I am thinking of the details that I have to also say them out loud to her!

As for the hobby, books and studying for me! All of your responses will help me to get to where I am trying to go. I am grateful for your kindness and patience.

thanks,

Carlos
 
OK, now we're getting somewhere! Butter motley X anery motley bloodred will produce 100% normal motleys het amel anery caramel bloodred. Pair those offspring to each other and then you'll get your motley sulfur in the F2 generation along with a pile of other really nice morphs.
 
Susan many thanks!
It makes sense now! Since I have no matching recessive traits I get 100% normal looking each one carrying the hets of both male and female. :idea:

Thanks again,

Carlos
 
cmariles said:
Susan many thanks!
It makes sense now! Since I have no matching recessive traits I get 100% normal looking each one carrying the hets of both male and female. :idea:

Thanks again,

Carlos
Click to expand...

If both parents are motley you do have matching traits (motley). So you would get all motley offspring (with normal coloration). And with hets of the other morphs the parents carry.
 
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