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Punnet Square Help Please

Green Bean

Reptile Chick
Hey all-

This is a real basic one and I feel stupid for even posting the question, but I don't know and I don't want to guess.

I'd like to know the combonation of letters that are used for figuring out what I will get if I mate a Normal het Snow and an Anery. (I am assuming since the mother and father of these two are a Snow and a Normal that the Anery would be het Normal, correct?) Better yet let me see if I can do it an post it below. Some then can correct it.

Ns= Normal het Snow
aN= Anery

|N | s
a aN as
-
N NN Ns


So I'd get 3 babies showing normal, one het anery, one het snow, one normal with no hets, and an anery snow........which doesn't make sense because (it was explained to me once, I don't know how to explain it again...)

I am reading both SerpentineWidgets Genetics guide and Cornsnake manuel. I do best with pictures.... And I've only read serpentine widgets onces so I will be re Reading them again.

Please be kind and try not to laught too much! lol
 
I guess what I am trying to do if see how many snows I'd get by crossing and Anery and a Normal het Snow........now I am so confused I don't even know if it can be done....:headbang:

But from what I read and now remember is that a Snow a result of both an Anery and Amel mix, it has both the Anery and Amel genes. Right?
 
Crap, sorry I didn't mean to post so soon. So to get do a Punnet Square with a snow it would have to have both the amel and anery genes to show up on the square. aa and ee as is used in the serpentine widget example.
 
Green Bean said:
(I am assuming since the mother and father of these two are a Snow and a Normal that the Anery would be het Normal, correct?)

I'm sure someone will correct me if I'm wrong, but you can't have anything that is het Normal. Normal is a dominant gene, therefore anything carrying that gene will appear to be normal.
 
Can you have an anery het snow?

BeckyG said:
I'm sure someone will correct me if I'm wrong, but you can't have anything that is het Normal. Normal is a dominant gene, therefore anything carrying that gene will appear to be normal.
 
Green Bean said:
Can you have an anery het snow?


LMAO you guys can ignore this post till I can figure out somethings. I'll do more reading and come back to everyone later with something more intelligent.
 
Layna, are the 2 snakes you're talking about the 2 you got from me? If so you've got a Normal het Anery/Amel and an Anery het Amel. Your possibilities are:

Male is, Het for Snow
Female is, Anerythristic, Het for Amel
Offspring are predicted to be...
2/8, Anerythristic, Het for Amel
2/8, Het for Snow
1/8, Snow
1/8, Anerythristic
1/8, Amelanistic, Het for Anery
1/8, Het for Anery
 
Green Bean said:
LMAO you guys can ignore this post till I can figure out somethings. I'll do more reading and come back to everyone later with something more intelligent.
I think you are confusing yourself by treating "snow" as a single trait. For breeding purposes, snow should be expressed as anery and amel, the two morphs that are combined to create what is called a snow. That being said, your snakes are normal, het for both amel and anery, and an anery. The normal can pass its genes on in the following combinations:

amel but not anery
anery buy not amel
amel and anery
neither amel nor anery (normal)

The anery always passes on anery, so they would combine as:

amel but not anery plus anery equals normal, het amel and anery
anery but not amel plus anery equals anery
amel and anery plus anery equals anery, het amel
normal plus anery equals normal het anery

You will have anery babies with a 50% chance of being het for amel, and
normal babies that are het anery and have a 50% chance of being het for amel.
 
jaxom1957 said:
I think you are confusing yourself by treating "snow" as a single trait. For breeding purposes, snow should be expressed as anery and amel, the two morphs that are combined to create what is called a snow. That being said, your snakes are normal, het for both amel and anery, and an anery.


I understand up to here and then you lost me, LOL! I'll figure it out though. Thanks for your replies.
 
Green Bean said:
Hey all-

This is a real basic one and I feel stupid for even posting the question, but I don't know and I don't want to guess.

I'd like to know the combonation of letters that are used for figuring out what I will get if I mate a Normal het Snow and an Anery.

For lack of better ones:

Amelanistic locus "A"
Normal (not amelanistic) gene = A
Amelanistic gene = a
Anerythristic locus "E"
Normal (not anerythristic) gene = E
Anerythristic gene = e

Therefore, your Normal het snow would be Aa Ee (one copy of normal, one copy of amel = looks normal, carrying amel; one copy of normal, one copy of anery = looks normal, carrying anery)
Your Anery, if it had a snow parent, would be Aa ee (One copy of normal, one copy of amel - because a snow HAS to give an amel gene; two copies of Anery, so it looks anery)

So crossing Aa Ee with Aa ee gets you:

AA Ee (Normal het anery - since the anery HAS to give an anery gene, you know that every single offspring of this pair MUST be 100% het anery)
AA ee (Anery, no hets)
Aa Ee (Normal het snow)
Aa ee (Anery het amel)
aa Ee (Amel het anery)
aa ee (Amelanistic Anery = Snow)

Of course, the problem arises that you don't know whether you've got an AA or an Aa without test-breeding the offspring - that makes all visual normals 'possible het' amelanistics.

(I am assuming since the mother and father of these two are a Snow and a Normal that the Anery would be het Normal, correct?)

Nope - it actually means that the "normal" parent was 100% het anery (otherwise, it couldn't have produced an anerythristic offspring).

Certainly an animal can be "het" normal (carrying only one copy of the 'normal/not-mutation' gene on that gene pair) ... but that makes it LOOK normal, because wild-type not-mutation colourations in corn snakes (so far) are dominant genes.
 
This section is a lot more fun to read (for genetics beginners like me!!) when I have a copy of Morph Guide right beside me. I need one for home, and one for work!

Nanci
 
Green Bean said:
I understand up to here and then you lost me, LOL! I'll figure it out though. Thanks for your replies.
It can be tricky to understand at first. Try it this way:

Your male has to pass along either Amel or "Not Amel" (Normal) and either Anery or "Not Anery". Your female passes along Anery and either Amel or "Not Amel". The one sure thing is that all the offspring will be at least het for Anery, since the female always passes that. So, let's look at the babies and ask ourselves some questions.

Does the baby look snow? If so, it must have received Anery from both parents and Amel from both parents. We can guarantee the genetics as Anery and Amel, which is referred to as a "snow".

Does the baby look Amel? If so, it must have received Amel from both parents. We know it had to receive Anery from mom, but it must not have received it from dad. We can guarantee the genetics as Amel het Anery.

Those are the easy ones. The others don't allow us to be as accurate.

Does the baby look Anery? If so, it must have received Anery from both parents. What we cannot tell by looking is whether it received Amel from either dad or mom. We can guarantee the genetics as Anery, but only 66% possibly het for Amel.

Does the baby look normal? If so, we know it had to receive Anery from mom, but not from dad. What we cannot tell by looking is whether it received Amel from either dad or mom. We can guarantee the genetics as Normal het Anery, but only 66% possibly het for amel.

The 66% chance is the result of the four possible ways the Amel could be passed on to the offspring. One time out of four, Amel was passed by both parents; one time out of four, it was passed on by only the male; one time out of four, it was passed on by only the female; one time out of four, neither parent passed it on. We can ignore the offspring that received Amel from both, since we can see that result. That leaves three possibilities: Amel from only Dad, Amel from only Mom or NO Amel. Two out of three received amel from one parent, which gives the 66% possible het Amel.
 
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